`
ABSTRACT
RATIONALE
Note: In the prose, lazy sequences are known as lseqs throughout.
Here is a short list of the procedures provided by this SRFI.
lseq lseq* list->lseq vector->lseq string->lseq generator->lseq lseq-unfold lseq-unfold-right
lseq? null-lseq? lseq=
lseq-first lseq-second lseq-third lseq-fourth lseq-fifth lseq-sixth lseq-seventh lseq-eighth lseq-ninth lseq-tenth lseq-last lseq-rest lseq-ref lseq-take lseq-drop lseq-take-right lseq-drop-right isplit-at
lseq-length lseq-append lseq-concatenate lseq-reverse lseq-zip lseq-unzip1 lseq-unzip2 lseq-unzip3 lseq-unzip4 lseq-unzip5 lseq-count
lseq-map lseq-for-each lseq-fold lseq-fold-right lseq-fold lseq-fold-right lseq-reduce lseq-reduce-right
lseq-filter lseq-remove lseq-partition
lseq-member lseq-memq lseq-memv lseq-find lseq-find-rest lseq-any lseq-every lseq-index lseq-take-while lseq-drop-while lseq-span lseq-break
lseq-delete lseq-delete-neighbor-dups
lseq-assoc lseq-assq lseq-assv lseq-alist-cons lseq-alist-delete
lseq->list lseq-vector lseq->string lseq->generator
lseq-comparator make-lseq-comparator
lseq-realize! lseq-realize-once! lseq-realize-steps! lseq-realize-until!
The syntax keyword lq
is
provided as part of this SRFI. It is analogous to quote
,
taking an arbitrary number of literals and constructing an lseq from them,
with any pairs in the literals converted to ipairs. It is useful
for providing constant lazy sequences.
The templates given below obey the following conventions for procedure formals:
lseq | A lazy sequence |
---|---|
x, y, d, a | Any value |
object, value | Any value |
n, i | A natural number (an integer >= 0) |
proc | A procedure |
pred | A procedure whose return value is treated as a boolean |
generator | A procedure with no arguments that returns a sequence of values |
= | A boolean procedure taking two arguments |
To interpret the examples, pretend that they are executed on a Scheme that prints lazy sequences with the syntax of lists.
lseq
object ... -> lseq
Returns a newly allocated lseq of its arguments.
(lseq 'a (+ 3 4) 'c) => (a 7 c) (lseq) => ()
lseq*
elt1 elt2 ... -> lseq
Like lseq
,
but the last argument is an lseq. This is the lseq equivalent of both
cons and SRFI 1's
cons*
.
(lseq* 1 2 3 (lseq 4)) => (1 2 3 4)
list->lseq
list -> lseq
vector->lseq
vector -> lseq
string->lseq
string -> lseq
generator->lseq
generator -> lseq
Returns an lseq whose elements are the elements of list, vector, string, or the values generated by generator.
(list->lseq '(c c c c c)) => (c c c c) (vector->lseq #(c c c c c)) => (c c c c) (string->lseq "cccc") => (#\c #\c #\c #\c) (generator->lseq (circular-generator 'c)) => (c c c ...)
lseq-unfold
stop? mapper successor seed -> lseq
Creates a newly allocated lseq, and performs the following algorithm with the current seed set to seed:
If the result of applying the predicate stop? to the current seed is true, return the lseq. Otherwise, apply the procedure mapper to the current seed, returning a value which is appended to the lseq. Then get a new seed by applying the procedure successor to the current seed, and repeat this algorithm.
;; Lseq of squares: 1^2 ... 10^2 (lseq-unfold (lambda (x) (> x 10)) (lambda (x) (* x x)) (lambda (x) (+ x 1)) 1)
lseq-unfold-right
stop? mapper successor seed -> lseq
Creates a newly allocated lseq, and performs the following algorithm with the current seed set to seed:
If the result of applying the predicate stop? to the current seed is true, return the lseq. Otherwise, apply the procedure mapper to the current seed, returning a value which is prepended to the lseq. Then get a new seed by applying the procedure successor to the current seed, and repeat this algorithm.
;; Lseq of squares: 10^2 ... 1^2 (lseq-unfold (lambda (x) (> x 10)) (lambda (x) (* x x)) (lambda (x) (+ x 1)) 1)
lseq?
x -> boolean
Returns #t
iff x is an lseq, otherwise #f
.
null-lseq?
lseq -> boolean
This procedure returns #t
if
the argument is an empty lseq, and #f
otherwise.
lseq=
elt= lseq1 ... -> boolean
Determines lseq equality, given an element-equality procedure.
The lseq A equals the lseq B
if they are of the same length,
and their corresponding elements are equal,
as determined by elt=.
If the element-comparison procedure's first argument is
from lseqi,
then its second argument is from lseqi+1,
i.e. it is always called as
(elt= a b)
for a an element of lseq A,
and b an element of lseq B.
In the n-ary case,
every lseqi is compared to
lseqi+1
(as opposed, for example, to comparing
lseq1 to lseqi,
for i>1).
If there are no lseq arguments at all,
lseq=
simply returns true.
Note that the dynamic order in which the elt= procedure is
applied to pairs of elements is not specified.
For example, if lseq=
is applied
to three lseqs, A, B, and C,
it may first completely compare A to B,
then compare B to C,
or it may compare the first elements of A and B,
then the first elements of B and C,
then the second elements of A and B, and so forth.
The equality procedure must be consistent with eq?
.
That is, it must be the case that
(eq? x y)
=> (elt= x y)
.
Note that this implies that two lseqs which are eq?
are always lseq=
, as well; implementations may exploit this
fact to "short-cut" the element-by-element comparisons.
(lseq= eq?) => #t ; Trivial cases (lseq= eq? (lq a)) => #t
lseq-first
lseq -> object
lseq-second
lseq -> object
lseq-third
lseq -> object
lseq-fourth
lseq -> object
lseq-fifth
lseq -> object
lseq-sixth
lseq -> object
lseq-seventh
lseq -> object
lseq-eighth
lseq -> object
lseq-ninth
lseq -> object
lseq-tenth
lseq -> object
lseq-last
lseq -> object
Returns the first, second, ..., tenth, last element of lseq.
(lseq-third (lq a b c d e)) => c
lseq-rest
lseq -> lseq
Returns an lseq with the contents of lseq except for the first element. Note that it is an error to apply it to an empty lseq.
(lseq-first (lq a b c)) => a (lseq-rest (lq a b c)) => (b c) (lseq-first (lq (a) b c d)) => (a) (lseq-rest (lq (a) b c d)) => (b c d) (lseq-first (lseq-pair 1 2)) => 1 (lseq-rest (lseq-pair 1 2)) => 2 (lseq-first '()) => *error* (lseq-rest '()) => *error*
lseq-ref
lseq i -> value
Returns the ith element of lseq.
(This is the same as
(lseq-first (lseq-drop lseq i))
.)
It is an error if i >= n,
where n is the length of lseq.
(lseq-ref (lq a b c d) 2) => c
lseq-take
lseq i -> lseq
lseq-drop
lseq i -> object
lseq-take
returns the first i elements of lseq.
lseq-drop
returns all but the first i elements of lseq.
(lseq-take (lq a b c d e) 2) => (a b) (lseq-drop (lq a b c d e) 2) => (c d e)
For a legal i, lseq-take
and lseq-drop
partition lseq in a manner which
can be inverted with lseq-append
:
(lseq-append (lseq-take lseq i) (lseq-drop lseq i)) = lseq
lseq-drop
is exactly equivalent to performing i lseq-rest
operations on lseq.
lseq-take-right
lseq i -> object
lseq-drop-right
lseq i -> lseq
lseq-take-right
returns the last i elements of lseq.
lseq-drop-right
returns all but the last i elements of lseq.
(lseq-take-right (lq a b c d e) 2) => (d e) (lseq-drop-right (lq a b c d e) 2) => (a b c)
For a legal i, lseq-take-right
and lseq-drop-right
partition lseq in a manner
which can be inverted with lseq-append
:
(lseq-append (lseq-take lseq i) (lseq-drop lseq i)) = lseq
lseq-take-right
's return value is guaranteed to share a common tail with lseq.
lseq-split-at
lseq i -> [lseq object]
Splits the lseq lseq at index i, returning two values, an lseq of the first i elements, and an lseq of the remaining elements. It is equivalent to
(values (lseq-take lseq i) (lseq-drop lseq i))
lseq-length
lseq -> integer
Returns the length of its argument, which is the non-negative integer n such that lseq-last
applied n times to the lseq produces an empty lseq.
lseq-append
lseq1 ... -> lseq
Returns an lseq consisting of the elements of lseq1 followed by the elements of the other lseq parameters.
(lseq-append (lq x) (lq y)) => (x y) (lseq-append (lq a) (lq b c d)) => (a b c d) (lseq-append (lq a (b)) (lq (c))) => (a (b) (c))
The resulting lseq is always newly allocated, except that it shares structure with the final lseqi argument.
(lseq-append (lq a b) (lseq-pair 'c 'd)) => (a b c . d) (lseq-append '() 'a) => a (lseq-append (lq x y)) => (x y) (lseq-append) => ()
lseq-concatenate
list-of-lseqs -> value
Appends the elements of its argument together.
Note that some Scheme implementations do not support passing more than a
certain number (e.g., 64) of arguments to an n-ary procedure.
In these implementations, the (apply lseq-append ...)
idiom
would fail when applied to long lists,
but lseq-concatenate
would continue to function properly.
lseq-reverse
lseq -> lseq
Returns a newly allocated lseq consisting of the elements of lseq in reverse order.
(lseq-reverse (lq a b c)) => (c b a) (lseq-reverse (lq a (b c) d (e (f)))) => ((e (f)) d (b c) a)
lseq-append-reverse
rev-head tail -> lseq
lseq-append-reverse
returns
(lseq-append (lseq-reverse rev-head) tail)
.
It is provided because it is a common operation — a common
list-processing style calls for this exact operation to transfer values
accumulated in reverse order onto the front of another lseq, and because
the implementation is significantly more efficient than the simple
composition it replaces. (But note that this pattern of iterative
computation followed by a reverse can frequently be rewritten as a
recursion, dispensing with the reverse
and lseq-append-reverse
steps, and
shifting temporary, intermediate storage from the heap to the stack,
which is typically a win for reasons of cache locality and eager storage
reclamation.)
lseq-zip
lseq1 lseq2 ... -> lseq
If lseq-zip
is passed n lseqs, it returns an lseq as long as the shortest
of these lseqs, each element of which is an n-element list comprised
of the corresponding elements from the arguments.
(lseq-zip (lq one two three) (lq 1 2 3) (lq odd even odd even odd even odd even)) => ((one 1 odd) (two 2 even) (three 3 odd)) (lseq-zip (lq 1 2 3)) => ((1) (2) (3))
lseq-unzip1
list-of-lseqs -> lseq
lseq-unzip2
list-of-lseqs -> [lseq lseq]
lseq-unzip3
list-of-lseqs -> [lseq lseq lseq]
lseq-unzip4
list-of-lseqs -> [lseq lseq lseq lseq]
lseq-unzip5
lslist-of-lseqs eq -> [lseq lseq lseq lseq lseq]
lseq-unzip1
takes a list of lseqs,
where every lseq must contain at least one element,
and returns an lseq containing the initial element of each such lseq.
That is, it returns (lseq-map lseq-first lseqs)
.
lseq-unzip2
takes a list of lseqs, where every lseq must contain at least
two elements, and returns two values: an lseq of the first elements,
and an lseq of the second elements. lseq-unzip3
does the same for the first
three elements of the lseqs, and so forth.
(lseq-unzip2 (list (lq 1 one) (lq 2 two) (lq 3 three))) => (1 2 3) (one two three)
lseq-count
pred lseq1 lseq2 ... -> integer
pred is a procedure taking as many arguments as there
are lseqs and returning a single value. It is applied
element-wise to the elements of the lseqs, and a count is
tallied of the number of elements that produce a true value. This count
is returned. count
is "iterative" in that it is guaranteed
to apply pred to the lseq elements in a
left-to-right order.
The counting stops when the shortest lseq expires.
(count even? (lq 3 1 4 1 5 9 2 5 6)) => 3 (count < (lq 1 2 4 8) (lq 2 4 6 8 10 12 14 16)) => 3
lseq-fold
kons knil lseq1 lseq2 ... -> value
The fundamental lseq iterator.
First, consider the single lseq-parameter case. If lseq1 = (e1 e2 ... en), then this procedure returns
(kons en ... (kons e2 (kons e1 knil)) ... )
That is, it obeys the (tail) recursion
(lseq-fold kons knil lis) = (lseq-fold kons (kons (lseq-first lis) knil) (lseq-last lis)) (lseq-fold kons knil '()) = knilExamples:
(lseq-fold + 0 lis) ; Add up the elements of LIS. (lseq-fold lseq* (lseq) lseq) ; Reverse lseq. (lseq-fold lseq* tail rev-head) ; See append-reverse. ;; How many symbols in LIS? (lseq-fold (lambda (x count) (if (symbol? x) (+ count 1) count)) 0 lseq) ;; Length of the longest string in lseq: (lseq-fold (lambda (s max-len) (max max-len (string-length s))) 0 lseq)
If n lseq arguments are provided, then the kons function must take n+1 parameters: one element from each lseq, and the "seed" or fold state, which is initially knil. The fold operation terminates when the shortest lseq runs out of values:
(lseq-fold ipair* '() (lq a b c) (lq 1 2 3 4 5)) => (c 3 b 2 a 1)
lseq-fold-right
kons knil lseq1 lseq2 ... -> value
The fundamental lseq recursion operator.
First, consider the single lseq-parameter case. If lseq1 = (e1 e2 ... en)
,
then this procedure returns
(kons e1 (kons e2 ... (kons en knil)))
That is, it obeys the recursion
(lseq-fold-right kons knil lis) = (kons (lseq-first lis) (lseq-fold-right kons knil (lseq-last lis))) (lseq-fold-right kons knil '()) = knilExamples:
(lseq-fold-right ipair '() lseq) ; Copy lseq. ;; Filter the even numbers out of lseq. (lseq-fold-right (lambda (x l) (if (even? x) (lseq-pair x l) l)) '() lseq))
If n lseq arguments are provided, then the kons procedure must take n+1 parameters: one element from each lseq, and the "seed" or fold state, which is initially knil. The fold operation terminates when the shortest lseq runs out of values:
(lseq-fold-right lseq* '() (lq a b c) (lq 1 2 3 4 5)) => (a 1 b 2 c 3)
lseq-reduce
f ridentity lseq -> value
lseq-reduce
is a variant of lseq-fold
.
ridentity should be a "right identity" of the procedure f — that is, for any value x acceptable to f,
(f x ridentity) = x
lseq-reduce
has the following definition:
(lseq-fold f (lseq-first lseq) (lseq-last lseq))
.
(lseq-fold f ridentity lseq)
.
Note that ridentity is used only in an empty-lseq case.
You typically use lseq-reduce
when applying f is expensive and you'd
like to avoid the extra application incurred when lseq-fold
applies
f to the head of lseq and the identity value,
redundantly producing the same value passed in to f.
For example, if f involves searching a file directory or
performing a database query, this can be significant.
In general, however, lseq-fold
is useful
in many contexts where lseq-reduce
is not
(consider the examples given in the lseq-fold
definition — only one of the
folds uses a function with a right identity.
The other four may not be performed with lseq-reduce
).
;; take the max of an lseq of non-negative integers. (lseq-reduce max 0 nums)
lseq-reduce-right
f ridentity lseq -> value
lseq-reduce-right
is the fold-right variant of lseq-reduce
.
It obeys the following definition:
(lseq-reduce-right f ridentity '()) = ridentity (lseq-reduce-right f ridentity (lq e1)) = (f e1 ridentity) = e1 (lseq-reduce-right f ridentity (lq e1 e2 ...)) = (f e1 (lseq-reduce f ridentity (e2 ...)))
...in other words, we compute
(lseq-fold-right f ridentity lseq)
.
;; Append a bunch of lseqs together. (lseq-reduce-right lseq-append '() lseq-of-lseqs)
lseq-map
proc lseq1 lseq2 ... -> lseq
proc is a procedure taking as many arguments
as there are lseq arguments and returning a single value.
lseq-map
applies proc element-wise to the elements
of the lseqs and returns an lseq of the results,
in order.
The dynamic order in which proc
is applied to the elements of the lseqs is unspecified.
(lseq-map icadr (lq (a b) (d e) (g h))) => (b e h) (lseq-map (lambda (n) (expt n n)) (lq 1 2 3 4 5)) => (1 4 27 256 3125) (lseq-map + (lq 1 2 3) (lq 4 5 6)) => (5 7 9) (let ((count 0)) (lseq-map (lambda (lseq-gnored) (set! count (+ count 1)) count) (lq a b))) => (1 2) or (2 1)
lseq-for-each
proc lseq1 lseq2 ... -> unspecified
The arguments to lseq-for-each
are like the arguments to
lseq-map
, but
lseq-for-each
calls proc for its side effects rather
than for its values.
Unlike lseq-map
, lseq-for-each
is guaranteed to call
proc on the elements of the lseqs in order from the first
element(s) to the last,
and the value returned by lseq-for-each
is unspecified.
(let ((v (make-vector 5))) (lseq-for-each (lambda (lseq-) (vector-set! v i (* i i))) (lq 0 1 2 3 4)) v) => #(0 1 4 9 16)
lseq-append-map
f lseq1 lseq2 ... -> value
Map f over the elements of the lseqs, just as in the lseq-map
function.
However, the results of the applications are appended together (using lseq-append
) to
make the final result.
The dynamic order in which the various applications of f are made is not specified.
Example:
(lseq-append-map (lambda (x) (lseq x (- x))) (lq 1 3 8)) => (1 -1 3 -3 8 -8)
lseq-filter
pred lseq -> lseq
Return all the elements of lseq that satisfy predicate pred. The lseq is not disordered — elements that appear in the result lseq occur in the same order as they occur in the argument lseq. The returned lseq may share a common tail with the argument lseq. The dynamic order in which the various applications of pred are made is not specified.
(lseq-filter even? (lq 0 7 8 8 43 -4)) => (0 8 8 -4)
lseq-remove
pred lseq -> lseq
(lambda (pred lseq) (lseq-filter (lambda (x) (not (pred x))) lseq))
The lseq is not disordered — elements that appear in the result lseq occur in the same order as they occur in the argument lseq. The returned lseq may share a common tail with the argument lseq. The dynamic order in which the various applications of pred are made is not specified.
(lseq-remove even? (lq 0 7 8 8 43 -4)) => (7 43)
lseq-partition
pred lseq -> [lseq lseq]
Partitions the elements of lseq with predicate pred, and returns two values: the lseq of in-elements and the lseq of out-elements. The lseq is not disordered — elements occur in the result lseqs in the same order as they occur in the argument lseq. The dynamic order in which the various applications of pred are made is not specified. One of the returned lseqs may share a common tail with the argument lseq.
(lseq-partition symbol? (lq one 2 3 four five 6)) => (one four five) (2 3 6)
The following procedures all search lseqs for the leftmost element satisfying some criteria.
lseq-find
pred lseq -> value
Return the first element of lseq that satisfies predicate pred; false if no element does.
(lseq-find even? (lq 3 1 4 1 5 9)) => 4
Note that lseq-find
has an ambiguity in its lookup semantics — if lseq-find
returns #f
, you cannot tell (in general) if it found a #f
element
that satisfied pred, or if it did not find any element at all. In
many situations, this ambiguity cannot arise — either the lseq being
searched is known not to contain any #f
elements, or the lseq is
guaranteed to have an element satisfying pred. However, in cases
where this ambiguity can arise, you should use lseq-find-tail
instead of
lseq-find
— lseq-find-tail
has no such ambiguity:
(cond ((lseq-find-tail pred lis) => (lambda (lseq-pair) ...)) ; Handle (lseq-first ipair) (else ...)) ; Search failed.
lseq-find-tail
pred lseq -> ipair or false
Return the longest tail of lseq whose first element satisfies pred. If no element does, return false.
lseq-find-tail
can be viewed as a general-predicate variant of the lseq-member
function.
Examples:
(lseq-find-tail even? (lq 3 1 37 -8 -5 0 0)) => (-8 -5 0 0) (lseq-find-tail even? (lq 3 1 37 -5)) => #f ;; imember x lseq: (lseq-find-tail (lambda (elt) (equal? x elt)) lseq)
lseq-find-tail
is essentially lseq-drop-while
,
where the sense of the predicate is inverted:
lseq-find-tail
searches until it finds an element satisfying
the predicate; lseq-drop-while
searches until it finds an
element that doesn't satisfy the predicate.
lseq-take-while
pred lseq -> lseq
Returns the longest initial prefix of lseq whose elements all satisfy the predicate pred.
(lseq-take-while even? (lq 2 18 3 10 22 9)) => (2 18)
lseq-drop-while
pred lseq -> lseq
Drops the longest initial prefix of lseq whose elements all satisfy the predicate pred, and returns the rest of the lseq.
(lseq-drop-while even? (lq 2 18 3 10 22 9)) => (3 10 22 9)
lseq-span
pred lseq -> [lseq lseq]
lseq-break
pred lseq -> [lseq lseq]
lseq-span
splits the lseq into the longest initial prefix whose
elements all satisfy pred, and the remaining tail.
lseq-break
inverts the sense of the predicate:
the tail commences with the first element of the input lseq
that satisfies the predicate.
In other words:
lseq-span
finds the initial span of elements
satisfying pred,
and lseq-break
breaks the lseq at the first element satisfying
pred.
lseq-span
is equivalent to
(values (lseq-take-while pred lseq) (lseq-drop-while pred lseq))
(lseq-span even? (lq 2 18 3 10 22 9)) => (2 18) (3 10 22 9) (lseq-break even? (lq 3 1 4 1 5 9)) => (3 1) (4 1 5 9)
lseq-any
pred lseq1 lseq2 ... -> value
Applies the predicate across the lseqs, returning true if the predicate returns true on any application.
If there are n lseq arguments lseq1 ... lseqn, then pred must be a procedure taking n arguments and returning a boolean result.
lseq-any
applies pred to the first elements of the lseqi parameters.
If this application returns a true value, lseq-any
immediately returns
that value. Otherwise, it iterates, applying pred to the second
elements of the lseqi parameters, then the third, and so forth.
The iteration stops when a true value is produced or one of the lseqs runs
out of values; in
the latter case, lseq-any
returns #f
.
The application of pred to the last element of the
lseqs is a tail call.
Note the difference between lseq-find
and lseq-any
— lseq-find
returns the element
that satisfied the predicate; lseq-any
returns the true value that the
predicate produced.
Like lseq-every
, lseq-any
's name does not end with a question mark — this is to
indicate that it does not return a simple boolean (#t
or #f
), but a
general value.
(lseq-any integer? (lq a 3 b 2.7)) => #t (lseq-any integer? (lq a 3.1 b 2.7)) => #f (lseq-any < (lq 3 1 4 1 5) (lq 2 7 1 8 2)) => #t
lseq-every
pred lseq1 lseq2 ... -> value
Applies the predicate across the lseqs, returning true if the predicate returns true on every application.
If there are n lseq arguments lseq1 ... lseqn, then pred must be a procedure taking n arguments and returning a boolean result.
lseq-every
applies pred to the first elements of the lseqi parameters.
If this application returns false, lseq-every
immediately returns false.
Otherwise, it iterates, applying pred to the second elements of the
lseqi parameters, then the third, and so forth. The iteration stops
when a false value is produced or one of the lseqs runs out of values.
In the latter case, lseq-every
returns
the true value produced by its final application of pred.
The application of pred to the last element of the lseqs
is a tail call.
If one of the lseqi has no elements, lseq-every
simply returns #t
.
Like lseq-any
, lseq-every
's name does not end with a question mark — this is to
indicate that it does not return a simple boolean (#t
or #f
), but a
general value.
lseq-index
pred lseq1 lseq2 ... -> integer or false
Return the index of the leftmost element that satisfies pred.
If there are n lseq arguments lseq1 ... lseqn, then pred must be a function taking n arguments and returning a boolean result.
lseq-index
applies pred to the first elements of the lseqi parameters.
If this application returns true, lseq-index
immediately returns zero.
Otherwise, it iterates, applying pred to the second elements of the
lseqi parameters, then the third, and so forth. When it finds a tuple of
lseq elements that cause pred to return true, it stops and returns the
zero-based index of that position in the lseqs.
The iteration stops when one of the lseqs runs out of values; in this
case, lseq-index
returns #f
.
(lseq-index even? (lq 3 1 4 1 5 9)) => 2 (lseq-index < (lq 3 1 4 1 5 9 2 5 6) (lq 2 7 1 8 2)) => 1 (lseq-index = (lq 3 1 4 1 5 9 2 5 6) (lq 2 7 1 8 2)) => #f
lseq-member
x lseq [=] -> lseq
lseq-memq
x lseq -> lseq
lseq-memv
x lseq -> lseq
These procedures return the longest tail of lseq whose first element is
x, where the tails of lseq are the
non-empty lseqs returned by
(lseq-drop lseq i)
for i less than the length of lseq.
If x does
not occur in lseq, then #f
is returned.
lseq-memq
uses eq?
to compare x
with the elements of lseq,
while lseq-memv
uses eqv?
, and
lseq-member
uses =, which defaults to equal?
.
(lseq-memq 'a (lq a b c)) => (a b c) (lseq-memq 'b (lq a b c)) => (b c) (lseq-memq 'a (lq b c d)) => #f (lseq-memq (lseq 'a) (lq b (a) c)) => #f (lseq-member (lseq 'a) (lq b (a) c)) => ((a) c) (lseq-memq 101 (lq 100 101 102)) => *unspecified* (lseq-memv 101 (lq 100 101 102)) => (101 102)
The comparison procedure is used to compare the elements ei of lseq to the key x in this way:
(= x ei) ; lseq is (E1 ... En)
That is, the first argument is always x, and the second argument is
one of the lseq elements. Thus one can reliably find the first element
of lseq that is greater than five with
(lseq-member 5 lseq <)
Note that fully general lseq searching may be performed with
the lseq-find-tail
and lseq-find
procedures, e.g.
(lseq-find-tail even? lseq) ; Find the first elt with an even key.
lseq-delete
x lseq [=] -> lseq
lseq-delete
uses the comparison procedure =,
which defaults to equal?
, to find
all elements of lseq that are equal to x, and deletes them from lseq. The
dynamic order in which the various applications of = are made is not
specified.
The lseq is not disordered — elements that appear in the result lseq occur in the same order as they occur in the argument lseq. The result may share a common tail with the argument lseq.
Note that fully general element deletion can be performed with the lseq-remove
procedures, e.g.:
;; delete all the even elements from lseq: (lseq-remove even? lseq)
The comparison procedure is used in this way:
(= x ei)
.
That is, x is always the first argument,
and an lseq element is always the
second argument. The comparison procedure will be used to compare each
element of lseq exactly once; the order in which it is applied to the
various ei is not specified. Thus, one can reliably remove all the
numbers greater than five from an lseq with
(lseq-delete 5 lseq <)
lseq-delete-neighbor-dups
lseq [=] -> lseq
lseq-delete-neighbor-dups
removes consecutive duplicate elements from the
lseq argument.
If there are multiple equal elements in the argument lseq, the result lseq
only contains the first or leftmost of these elements.
The order of these surviving elements is the same as in the original
lseq — lseq-delete-duplicates
does not disorder the lseq (hence it is useful
for "cleaning up" lazy association lists).
The = parameter is used to compare the elements of the lseq; it defaults
to equal?
. If x comes before y in lseq,
then the comparison is performed
(= x y)
.
The comparison procedure will be used to compare each pair of elements in
lseq no more than once;
the order in which it is applied to the various pairs is not specified.
Implementations of lseq-delete-duplicates
are allowed to share common tails
between argument and result lseqs — for example, if the lseq argument
contains only unique elements, it may simply return exactly
this lseq.
(lseq-delete-duplicates (lq a b a c a b c z)) => (a b c z) ;; Clean up an lazy alist: (lseq-delete-neighbor-dups (lq (a . 3) (b . 7) (a . 9) (c . 1)) (lambda (x y) (eq? (lseq-first x) (lseq-first y)))) => ((a . 3) (b . 7) (c . 1))
An "lazy association list" (or "lazy alist") is an lseq of pairs. The car of each pair contains a key value, and the cdr contains the associated data value. They can be used to construct simple look-up tables in Scheme. Note that lazy alists are probably inappropriate for performance-critical use on large data; in these cases, immutable maps or some other alternative should be employed.
lseq-assoc
key lazy-alist [=] -> ipair or #f
lseq-assq
key lazy-alist -> ipair or #f
lseq-assv
key lazy-alist -> ipair or #f
These procedures
find the first pair in lazy-alist whose car field is key,
and returns that pair.
If no ipair in lazy-alist has key as its icar,
then #f
is returned.
lseq-assq
uses eq?
to compare key
with the car fields of the ipairs in lazy-alist,
while lseq-assv
uses eqv?
and lseq-assoc
uses =, which defaults to equal?
.
(define e (lq (a 1) (b 2) (c 3))) (lseq-assq 'a e) => (a 1) (lseq-assq 'b e) => (b 2) (lseq-assq 'd e) => #f (lseq-assq (lseq 'a) (lq ((a)) ((b)) ((c)))) => #f (lseq-assoc (lseq 'a) (lq ((a)) ((b)) ((c)))) => ((a)) (lseq-assq 5 (lq (2 3) (5 7) (11 13))) => *unspecified* (lseq-assv 5 (lq (2 3) (5 7) (11 13))) => (5 7)
The comparison procedure is used to compare the elements ei of lseq to the key parameter in this way:
(= key (lseq-first ei)) ; lseq is (E1 ... En)
(lseq-assoc 5 lazy alist <)
Note that fully general lazy alist searching may be performed with
the lseq-find-tail
and lseq-find
procedures, e.g.
;; Look up the first association in lazy alist with an even key: (lseq-find (lambda (a) (even? (lseq-first a))) lazy alist)
lseq-alist-cons
key datum lazy-alist -> lazy alist
(lambda (key datum lazy-alist) (lseq* (cons key datum) lazy-alist))
Construct a new lazy alist entry mapping key -> datum in front of lazy alist.
lseq-alist-delete
key lazy-alist [=] -> lazy alist
lseq-alist-delete
deletes all associations from lazy-alist with the given key,
using key-comparison procedure =, which defaults to equal?
.
The dynamic order in which the various applications of = are made is not
specified.
Return values may share common tails with the lazy-alist argument. The lazy alist is not disordered — elements that appear in the result lazy alist occur in the same order as they occur in the argument lazy alist.
The comparison procedure is used to compare the element keys ki of lazy alist's
entries to the key parameter in this way:
(= key ki)
.
Thus, one can reliably remove all entries of lazy alist whose key is greater
than five with
(lseq-alist-delete 5 lazy alist <)
These procedures convert between mutable and immutable pair structures.
lseq->list
lseq -> list
lseq->vector
lseq -> vector
lseq->string
lseq -> string
lseq->generator
lseq -> generator
These procedures return a list, a vector, a string, or a generator that have the same elements as the argument.
lseq-pair-comparator
The lseq-comparator
object is a SRFI-114 comparator suitable for comparing lseqs.
Note that it is not a procedure.
It compares lseqs using default-comparator
on their first elements. If they are not equal, that value is returned. If they are equal, lseq-comparator
is used on the lseq-rest
of the lseqs and that value is returned.
make-lseq-comparator
comparator -> comparator
The make-lseq-comparator
procedure returns a comparator suitable for comparing lseqs
using element-comparator to compare the elements.
These procedures have no directly visible effects on their lseq arguments. However, they force the generator inside the lazy sequence to produce all its arguments and store them internally, which means that later operations may be faster, particularly if the generator is slow. They return an unspecified value.
realize!
lseq
Realizes all the values of lseq.
realize-once!
lseq
Realizes exactly one additional value of lseq. If no additional values are available, does nothing.
realize-steps!
lseq n
Realizes at most n values of lseq.
realize-until!
lseq pred
Realizes values of lseq until at least one value satisfies pred.
An lseq is a SRFI 117 queue plus a generator. Queues can be shared between lseqs, which means that you are not allowed to remove anything from them, and the only addition operation is lseq-realize-once!
, which realizes one value and adds it to the back of the queue.
The sample implementation of this SRFI depends on SRFI 9 (or R7RS) records. The files in the implementation are as follows:
FIXME
Without the work of Olin Shivers on SRFI 1, this SRFI would not exist. Everyone acknowledged there is transitively acknowledged here. This is not to imply that either Olin or anyone else necessarily endorses the final results, of course.