`
ABSTRACT
RATIONALE
Note: In the prose, lazy sequences are known as lseqs throughout.
Here is a short list of the procedures provided by this SRFI.
lseq lseq* list->lseq vector->lseq string->lseq generator->lseq lseq-unfold lseq-unfold-right
lseq? null-lseq? lseq=
lseq-ref lseq-first lseq-second lseq-third lseq-fourth lseq-fifth lseq-sixth lseq-seventh lseq-eighth lseq-ninth lseq-tenth lseq-rest lseq-take lseq-drop lseq-take-right lseq-drop-right isplit-at
lseq-length lseq-append lseq-concatenate lseq-reverse lseq-zip lseq-unzip1 lseq-unzip2 lseq-unzip3 lseq-unzip4 lseq-unzip5 lseq-count
lseq-map lseq-for-each lseq-fold lseq-fold-right lseq-fold lseq-fold-right lseq-reduce lseq-reduce-right
lseq-filter lseq-partition lseq-remove
lseq-member lseq-memq lseq-memvlseq-find lseq-find-rest lseq-any lseq-every lseq-index lseq-take-while lseq-drop-while lseq-span lseq-break
lseq-delete lseq-delete-neighbor-dups
lseq-assoc lseq-assq lseq-assv lseq-alist-cons lseq-alist-delete
replace-icar replace-icdr
lseq->list lseq-vector lseq->string lseq->generator
iapply
lseq-comparator make-lseq-comparator
lseq-realize! lseq-realize-once! lseq-realize-steps! lseq-realize-while!
The syntax keyword lq
is
provided as part of this SRFI. It is analogous to quote
,
taking an arbitrary number of literals and constructing an lseq from them,
with any pairs in the literals converted to ipairs. It is useful
for providing constant lazy sequences.
The templates given below obey the following conventions for procedure formals:
lseq | A proper (() -terminated) lseq
|
---|---|
lseq | A proper or dotted lseq |
ipair | An immutable pair |
x, y, d, a | Any value |
object, value | Any value |
n, i | A natural number (an integer >= 0) |
proc | A procedure |
pred | A procedure whose return value is treated as a boolean |
= | A boolean procedure taking two arguments |
To interpret the examples, pretend that they are executed on a Scheme that prints lazy sequences with the syntax of lists.
It is an error to pass a dotted lseq to a procedure not defined to accept such an argument.
(lseq* 1 2 3 (lseq 4)) => (1 2 3 4)
list->lseq
list -> lseq
vector->lseq
vector -> lseq
list->lseq
string -> lseq
list->lseq
generator -> lseq
(list->lseq '(c c c c c)) => (c c c c)
lseq-unfold
p f g seed [tail-gen] -> lseq
lseq-unfold
is best described by its basic recursion:
(lseq-unfold p f g seed) = (if (p seed) (tail-gen seed) (lseq-pair (f seed) (lseq-unfold p f g (g seed))))
(lambda (x) '())
In other words, we use g to generate a sequence of seed values
lseq-unfold
is the fundamental recursive lseq constructor,
just as lseq-fold-right
is
the fundamental recursive lseq consumer.
While lseq-unfold
may seem a bit abstract
to novice functional programmers, it can be used in a number of ways:
;; Lseq of squares: 1^2 ... 10^2 (lseq-unfold (lambda (x) (> x 10)) (lambda (x) (* x x)) (lambda (x) (+ x 1)) 1) (lseq-unfold null-lseq? icar icdr lis) ; Copy a proper lseq. ;; Read current input port into an lseq of values. (lseq-unfold eof-object? values (lambda (x) (read)) (read)) ;; Copy a possibly non-proper lseq: (lseq-unfold not-ipair? icar icdr lis values) ;; Append HEAD onto TAIL: (lseq-unfold null-lseq? icar icdr head (lambda (x) tail))Interested functional programmers may enjoy noting that
lseq-fold-right
and lseq-unfold
are in some sense inverses.
That is, given operations knull?, kar,
kdr, kons, and knil satisfying
(kons (kar x) (kdr x))
= x
and
(knull? knil)
= #t
(lseq-fold-right kons knil (lseq-unfold knull? kar kdr x))
= x
(lseq-unfold knull? kar kdr (lseq-fold-right kons knil x))
= x.
iunfold-right
p f g seed [tail] -> lseq
lseq-unfold-right
constructs an lseq with the following loop:
(let lp ((seed seed) (lis tail)) (if (p seed) lis (lp (g seed) (lseq-pair (f seed) lis))))
'()
.
In other words, we use g to generate a sequence of seed values
lseq-unfold-right
is the fundamental iterative lseq constructor,
just as lseq-fold
is the
fundamental iterative lseq consumer.
While lseq-unfold-right
may seem a bit abstract
to novice functional programmers, it can be used in a number of ways:
;; Lseq of squares: 1^2 ... 10^2 (lseq-unfold-right zero? (lambda (x) (* x x)) (lambda (x) (- x 1)) 10) ;; Reverse a proper lseq. (lseq-unfold-right null-lseq? icar icdr lis) ;; Read current input port into an lseq of values. (lseq-unfold-right eof-object? values (lambda (x) (read)) (read)) ;; (lseq-append-reverse rev-head tail) (lseq-unfold-right null-lseq? icar icdr rev-head tail)Interested functional programmers may enjoy noting that
lseq-fold
and lseq-unfold-right
are in some sense inverses.
That is, given operations knull?, kar,
kdr, kons, and knil satisfying
(kons (kar x) (kdr x))
= x
and
(knull? knil)
= #t
(lseq-fold kons knil (lseq-unfold-right knull? kar kdr x))
= x
(lseq-unfold-right knull? kar kdr (lseq-fold kons knil x))
= x.
lseq?
x -> boolean
null-lseq?
lseq -> boolean
lseq=
elt= lseq1 ... -> boolean
(elt= a b)
for a an element of lseq A,
and b an element of lseq B.
In the n-ary case,
every lseqi is compared to
lseqi+1
(as opposed, for example, to comparing
lseq1 to lseqi,
for i>1).
If there are no lseq arguments at all,
lseq=
simply returns true.
Note that the dynamic order in which the elt= procedure is
applied to pairs of elements is not specified.
For example, if lseq=
is applied
to three lseqs, A, B, and C,
it may first completely compare A to B,
then compare B to C,
or it may compare the first elements of A and B,
then the first elements of B and C,
then the second elements of A and B, and so forth.
The equality procedure must be consistent with eq?
.
That is, it must be the case that
(eq? x y)
=> (elt= x y)
.
eq?
are always lseq=
, as well; implementations may exploit this
fact to "short-cut" the element-by-element comparisons.
(lseq= eq?) => #t ; Trivial cases (lseq= eq? (lq a)) => #t
ifirst
lseq -> object
isecond
lseq -> object
ithird
lseq -> object
ifourth
lseq -> object
ififth
lseq -> object
isixth
lseq -> object
iseventh
lseq -> object
ieighth
lseq -> object
ininth
lseq -> object
itenth
lseq -> object
(lseq-third (lq a b c d e)) => c
lseq-last
lseq -> lseq
(lseq-first (lq a b c)) => a (lseq-last (lq a b c)) => (b c) (lseq-first (lq (a) b c d)) => (a) (lseq-last (lq (a) b c d)) => (b c d) (lseq-first (lseq-pair 1 2)) => 1 (lseq-last (lseq-pair 1 2)) => 2 (lseq-first '()) => *error* (lseq-last '()) => *error*
lseq-ref
lseq i -> value
(lseq-first (lseq-drop lseq i))
.)
It is an error if i >= n,
where n is the length of lseq.
(lseq-ref (lq a b c d) 2) => c
lseq-take
lseq i -> lseq
lseq-drop
lseq i -> object
lseq-take
returns the first i elements of lseq.lseq-drop
returns all but the first i elements of lseq.(lseq-take (lq a b c d e) 2) => (a b) (lseq-drop (lq a b c d e) 2) => (c d e)For a legal i,
lseq-take
and lseq-drop
partition lseq in a manner which
can be inverted with lseq-append
:
(lseq-append (lseq-take lseq i) (lseq-drop lseq i)) = lseq
lseq-drop
is exactly equivalent to performing i lseq-rest
operations on lseq.
lseq-take-right
lseq i -> object
lseq-drop-right
lseq i -> lseq
lseq-take-right
returns the last i elements of lseq.lseq-drop-right
returns all but the last i elements of lseq.
(lseq-take-right (lq a b c d e) 2) => (d e) (lseq-drop-right (lq a b c d e) 2) => (a b c)For a legal i,
lseq-take-right
and lseq-drop-right
partition lseq in a manner
which can be inverted with lseq-append
:
(lseq-append (lseq-take lseq i) (lseq-drop lseq i)) = lseq
lseq-take-right
's return value is guaranteed to share a common tail with lseq.
isplit-at
lseq i -> [lseq object]
lseq-split-at
splits the lseq lseq
at index i, returning two values, an lseq of the
first i elements, and an lseq of the remaining tail. It is equivalent
to
(values (lseq-take lseq i) (lseq-drop lseq i))
ilast
ipair -> object
last-ipair
ipair -> ipair
last-ipair
returns the last ipair in the non-empty
lseq pair.
(lseq-last (lq a b c)) => c (last-ipair (lq a b c)) => (c)
ilength
lseq -> integer
lseq-length
which is not a proper
lseq (()
-terminated).
The length of a proper lseq is a non-negative integer n such that lseq-last
applied n times to the lseq produces the empty list.
iappend
lseq1 ... -> lseq
(lseq-append (lq x) (lq y)) => (x y) (lseq-append (lq a) (lq b c d)) => (a b c d) (lseq-append (lq a (b)) (lq (c))) => (a (b) (c))The resulting lseq is always newly allocated, except that it shares structure with the final lseqi argument. This last argument may be any value at all; an improper lseq results if it is not a proper lseq. All other arguments must be proper lseqs.
(lseq-append (lq a b) (lseq-pair 'c 'd)) => (a b c . d) (lseq-append '() 'a) => a (lseq-append (lq x y)) => (x y) (lseq-append) => ()
iconcatenate
lseq-of-lseqs -> value
lseq-concatenate
returns
(lseq-apply iappend lseq-of-lseqs)or, equivalently,
(lseq-reduce-right iappend '() lseq-of-lseqs)
Note that some Scheme implementations do not support passing more than a
certain number (e.g., 64) of arguments to an n-ary procedure.
In these implementations, the (lseq-apply iappend ...)
idiom
would fail when applied to long lists,
but lseq-concatenate
would continue to function properly.
As with lseq-append
,
the last element of the input list may be any value at all.
ireverse
lseq -> lseq
(lseq-reverse (lq a b c)) => (c b a) (lseq-reverse (lq a (b c) d (e (f)))) => ((e (f)) d (b c) a)
iappend-reverse
rev-head tail -> lseq
lseq-append-reverse
returns
(lseq-append (lseq-reverse rev-head) tail)
.
It is provided because it is a common operation — a common
list-processing style calls for this exact operation to transfer values
accumulated in reverse order onto the front of another lseq, and because
the implementation is significantly more efficient than the simple
composition it replaces. (But note that this pattern of iterative
computation followed by a reverse can frequently be rewritten as a
recursion, dispensing with the reverse
and lseq-append-reverse
steps, and
shifting temporary, intermediate storage from the heap to the stack,
which is typically a win for reasons of cache locality and eager storage
reclamation.)
izip
lseq1 lseq2 ... -> lseq
(lambda lseqs (lseq-apply imap lseq lseqs))If
lseq-zip
is passed n lseqs, it returns an lseq as long as the shortest
of these lseqs, each element of which is an n-element lseq comprised
of the corresponding elements from the parameter lseqs.
(lseq-zip (lq one two three) (lq 1 2 3) (lq odd even odd even odd even odd even)) => ((one 1 odd) (two 2 even) (three 3 odd)) (lseq-zip (lq 1 2 3)) => ((1) (2) (3))
iunzip1
lseq -> lseq
iunzip2
lseq -> [lseq lseq]
iunzip3
lseq -> [lseq lseq lseq]
iunzip4
lseq -> [lseq lseq lseq lseq]
iunzip5
lseq -> [lseq lseq lseq lseq lseq]
lseq-unzip1
takes an lseq of lseqs,
where every lseq must contain at least one element,
and returns an lseq containing the initial element of each such lseq.
That is, it returns (lseq-map icar lseqs)
.
lseq-unzip2
takes an lseq of lseqs, where every lseq must contain at least
two elements, and returns two values: an lseq of the first elements,
and an lseq of the second elements. lseq-unzip3
does the same for the first
three elements of the lseqs, and so forth.
(lseq-unzip2 (lq (1 one) (2 two) (3 three))) => (1 2 3) (one two three)
icount
pred lseq1 lseq2 ... -> integer
count
is "iterative" in that it is guaranteed
to apply pred to the lseq elements in a
left-to-right order.
The counting stops when the shortest lseq expires.
(count even? (lq 3 1 4 1 5 9 2 5 6)) => 3 (count < (lq 1 2 4 8) (lq 2 4 6 8 10 12 14 16)) => 3
ifold
kons knil lseq1 lseq2 ... -> value
First, consider the single lseq-parameter case. If lseq1 = (e1 e2 ... en), then this procedure returns
(kons en ... (kons e2 (kons e1 knil)) ... )
(lseq-fold kons knil lis) = (lseq-fold kons (kons (lseq-first lis) knil) (lseq-last lis)) (lseq-fold kons knil '()) = knilExamples:
(lseq-fold + 0 lis) ; Add up the elements of LIS. (lseq-fold ipair '() lis) ; Reverse LIS. (lseq-fold ipair tail rev-head) ; See APPEND-REVERSE. ;; How many symbols in LIS? (lseq-fold (lambda (x count) (if (symbol? x) (+ count 1) count)) 0 lis) ;; Length of the longest string in LIS: (lseq-fold (lambda (s max-len) (max max-len (string-length s))) 0 lis)If n lseq arguments are provided, then the kons function must take n+1 parameters: one element from each lseq, and the "seed" or fold state, which is initially knil. The fold operation terminates when the shortest lseq runs out of values:
(lseq-fold ipair* '() (lq a b c) (lq 1 2 3 4 5)) => (c 3 b 2 a 1)
ifold-right
kons knil lseq1 lseq2 ... -> value
First, consider the single lseq-parameter case. If lseq1 = (e1 e2 ... en)
,
then this procedure returns
(kons e1 (kons e2 ... (kons en knil)))
(lseq-fold-right kons knil lis) = (kons (lseq-first lis) (lseq-fold-right kons knil (lseq-last lis))) (lseq-fold-right kons knil '()) = knilExamples:
(lseq-fold-right ipair '() lis) ; Copy LIS. ;; Filter the even numbers out of LIS. (lseq-fold-right (lambda (x l) (if (even? x) (lseq-pair x l) l)) '() lis))If n lseq arguments are provided, then the kons procedure must take n+1 parameters: one element from each lseq, and the "seed" or fold state, which is initially knil. The fold operation terminates when the shortest lseq runs out of values:
(lseq-fold-right ipair* '() (lq a b c) (lq 1 2 3 4 5)) => (a 1 b 2 c 3)
ipair-fold
kons knil lseq1 lseq2 ... -> value
fold
, but kons is applied to successive sub-lseqs of the
lseqs, rather than successive elements — that is, kons is applied to the
ipairs making up the lists, giving this (tail) recursion:
(lseq-pair-fold kons knil lis) = (let ((tail (lseq-last lis)))
(lseq-pair-fold kons (kons lis knil) tail))
(lseq-pair-fold kons knil '()
) = knil
Example:
(lseq-pair-fold ipair '() (lq a b c)) => ((c) (b c) (a b c))
ipair-fold-right
kons knil lseq1 lseq2 ... -> value
lseq-fold-right
that lseq-pair-fold
holds with lseq-fold
.
Obeys the recursion
(lseq-pair-fold-right kons knil lis) =
(kons lis (lseq-pair-fold-right kons knil (lseq-last lis)))
(lseq-pair-fold-right kons knil '()
) = knil
Example:
(lseq-pair-fold-right ipair '() (lq a b c)) => ((a b c) (b c) (c))
ireduce
f ridentity lseq -> value
lseq-reduce
is a variant of lseq-fold
.
ridentity should be a "right identity" of the procedure f — that is, for any value x acceptable to f,
(f x ridentity) = x
lseq-reduce
has the following definition:
(lseq-fold f (lseq-first lseq) (lseq-last lseq))
.
(lseq-fold f ridentity lseq)
.
Note that ridentity is used only in the empty-list case.
You typically use lseq-reduce
when applying f is expensive and you'd
like to avoid the extra application incurred when lseq-fold
applies
f to the head of lseq and the identity value,
redundantly producing the same value passed in to f.
For example, if f involves searching a file directory or
performing a database query, this can be significant.
In general, however, lseq-fold
is useful in many contexts where lseq-reduce
is not
(consider the examples given in the lseq-fold
definition — only one of the
five folds uses a function with a right identity.
The other four may not be performed with lseq-reduce
).
;; take the max of an lseq of non-negative integers. (lseq-reduce max 0 nums) ; i.e., (lseq-apply max 0 nums)
ireduce-right
f ridentity lseq -> value
lseq-reduce-right
is the fold-right variant of lseq-reduce
.
It obeys the following definition:
(lseq-reduce-right f ridentity '()) = ridentity (lseq-reduce-right f ridentity (lq e1)) = (f e1 ridentity) = e1 (lseq-reduce-right f ridentity (lq e1 e2 ...)) = (f e1 (lseq-reduce f ridentity (e2 ...)))...in other words, we compute
(lseq-fold-right f ridentity lseq)
.
;; Append a bunch of lseqs together. ;; I.e., (lseq-apply iappend lseq-of-lseqs) (lseq-reduce-right iappend '() lseq-of-lseqs)
imap
proc lseq1 lseq2 ... -> lseq
lseq-map
applies proc element-wise to the elements
of the lseqs and returns an lseq of the results,
in order.
The dynamic order in which proc
is applied to the elements of the lseqs is unspecified.
(lseq-map icadr (lq (a b) (d e) (g h))) => (b e h) (lseq-map (lambda (n) (expt n n)) (lq 1 2 3 4 5)) => (1 4 27 256 3125) (lseq-map + (lq 1 2 3) (lq 4 5 6)) => (5 7 9) (let ((count 0)) (lseq-map (lambda (lseq-gnored) (set! count (+ count 1)) count) (lq a b))) => (1 2) or (2 1)
ifor-each
proc lseq1 lseq2 ... -> unspecified
lseq-for-each
are like the arguments to
lseq-map
, but
lseq-for-each
calls proc for its side effects rather
than for its values.
Unlike lseq-map
, lseq-for-each
is guaranteed to call
proc on the elements of the lseqs in order from the first
element(s) to the last,
and the value returned by lseq-for-each
is unspecified.
(let ((v (make-vector 5))) (lseq-for-each (lambda (lseq-) (vector-set! v i (* i i))) (lq 0 1 2 3 4)) v) => #(0 1 4 9 16)
iappend-map
f lseq1 lseq2 ... -> value
(lseq-apply iappend (lseq-map f lseq1 lseq2 ...))
(lseq-apply iappend (lseq-map f lseq1 lseq2 ...))
lseq-map
function.
However, the results of the applications are appended together (using lseq-append
) to
make the final result.
The dynamic order in which the various applications of f are made is not specified.
Example:
(lseq-append-map (lambda (x) (lseq x (- x))) (lq 1 3 8)) => (1 -1 3 -3 8 -8)
imap-in-order
f lseq1 lseq2 ... -> lseq
lseq-map
procedure that guarantees to apply f across
the elements of the lseqi arguments in a left-to-right order. This
is useful for mapping procedures that both have side effects and
return useful values.
ipair-for-each
f lseq1 lseq2 ... -> unspecific
lseq-for-each
, but f is applied to successive sub-lseqs of the argument
lseqs. That is, f is applied to the cells of the lseqs, rather
than the lseqs' elements. These applications occur in left-to-right
order.
(lseq-pair-for-each (lambda (lseq-pair) (display ipair) (newline)) (lq a b c)) ==> (a b c) (b c) (c)
ifilter-map
f lseq1 lseq2 ... -> lseq
lseq-map
, but only true values are saved.
(lseq-filter-map (lambda (x) (and (number? x) (* x x))) (lq a 1 b 3 c 7)) => (1 9 49)The dynamic order in which the various applications of f are made is not specified.
ifilter
pred lseq -> lseq
(lseq-filter even? (lq 0 7 8 8 43 -4)) => (0 8 8 -4)
ipartition
pred lseq -> [lseq lseq]
(lseq-partition symbol? (lq one 2 3 four five 6)) => (one four five) (2 3 6)
iremove
pred lseq -> lseq
(lambda (pred lseq) (lseq-filter (lambda (x) (not (pred x))) lseq))The lseq is not disordered — elements that appear in the result lseq occur in the same order as they occur in the argument lseq. The returned lseq may share a common tail with the argument lseq. The dynamic order in which the various applications of pred are made is not specified.
(lseq-remove even? (lq 0 7 8 8 43 -4)) => (7 43)
The following procedures all search lseqs for a leftmost element satisfying some criteria. This means they do not always examine the entire lseq; thus, there is no efficient way for them to reliably detect and signal an error when passed a dotted lseq. Here are the general rules describing how these procedures work when applied to different kinds of lseqs:
In brief, compliant code may not pass a dotted lseq argument to these procedures.
Here are some examples, using the lseq-find
and lseq-any
procedures as canonical
representatives:
;; Proper lseq — success (lseq-find even? (lq 1 2 3)) => 2 (lseq-any even? (lq 1 2 3)) => #t ;; proper lseq — failure (lseq-find even? (lq 1 7 3)) => #f (lseq-any even? (lq 1 7 3)) => #f ;; Failure is error on a dotted lseq. (lseq-find even? (lseq-pair (1 (lseq-pair 3 x))) => error (lseq-any even? (lseq-pair (1 (lseq-pair 3 x))) => error ;; The dotted lseq contains an element satisfying the search. ;; This case is not specified — it could be success, an error, ;; or some third possibility. (lseq-find even? (lseq-pair (1 (lseq-pair 2 x))) => error/undefined (lseq-any even? (lseq-pair (1 (lseq-pair 2 x)))) => error/undefined ; success, error or other.
ifind
pred lseq -> value
(lseq-find even? (lq 3 1 4 1 5 9)) => 4Note that
lseq-find
has an ambiguity in its lookup semantics — if lseq-find
returns #f
, you cannot tell (lseq-n general) if it found a #f
element
that satisfied pred, or if it did not find any element at all. In
many situations, this ambiguity cannot arise — either the lseq being
searched is known not to contain any #f
elements, or the lseq is
guaranteed to have an element satisfying pred. However, in cases
where this ambiguity can arise, you should use lseq-find-tail
instead of
lseq-find
— lseq-find-tail
has no such ambiguity:
(cond ((lseq-find-tail pred lis) => (lambda (lseq-pair) ...)) ; Handle (lseq-first ipair) (else ...)) ; Search failed.
ifind-tail
pred lseq -> ipair or false
lseq-find-tail
can be viewed as a general-predicate variant of the lseq-member
function.
Examples:
(lseq-find-tail even? (lq 3 1 37 -8 -5 0 0)) => (-8 -5 0 0) (lseq-find-tail even? (lq 3 1 37 -5)) => #f ;; IMEMBER X LIS: (lseq-find-tail (lambda (elt) (equal? x elt)) lis)
lseq-find-tail
is essentially lseq-drop-while
,
where the sense of the predicate is inverted:
lseq-find-tail
searches until it finds an element satisfying
the predicate; lseq-drop-while
searches until it finds an
element that doesn't satisfy the predicate.
itake-while
pred lseq -> lseq
(lseq-take-while even? (lq 2 18 3 10 22 9)) => (2 18)
idrop-while
pred lseq -> lseq
(lseq-drop-while even? (lq 2 18 3 10 22 9)) => (3 10 22 9)
ispan
pred lseq -> [lseq lseq]
ibreak
pred lseq -> [lseq lseq]
lseq-span
splits the lseq into the longest initial prefix whose
elements all satisfy pred, and the remaining tail.
lseq-break
inverts the sense of the predicate:
the tail commences with the first element of the input lseq
that satisfies the predicate.
In other words:
lseq-span
finds the initial span of elements
satisfying pred,
and lseq-break
breaks the lseq at the first element satisfying
pred.
lseq-span
is equivalent to
(values (lseq-take-while pred lseq) (lseq-drop-while pred lseq))
(lseq-span even? (lq 2 18 3 10 22 9)) => (2 18) (3 10 22 9) (lseq-break even? (lq 3 1 4 1 5 9)) => (3 1) (4 1 5 9)
iany
pred lseq1 lseq2 ... -> value
If there are n lseq arguments lseq1 ... lseqn, then pred must be a procedure taking n arguments and returning a boolean result.
lseq-any
applies pred to the first elements of the lseqi parameters.
If this application returns a true value, lseq-any
immediately returns
that value. Otherwise, it iterates, applying pred to the second
elements of the lseqi parameters, then the third, and so forth.
The iteration stops when a true value is produced or one of the lseqs runs
out of values; in
the latter case, lseq-any
returns #f
.
The application of pred to the last element of the
lseqs is a tail call.
Note the difference between lseq-find
and lseq-any
— lseq-find
returns the element
that satisfied the predicate; lseq-any
returns the true value that the
predicate produced.
Like lseq-every
, lseq-any
's name does not end with a question mark — this is to
indicate that it does not return a simple boolean (#t
or #f
), but a
general value.
(lseq-any integer? (lq a 3 b 2.7)) => #t (lseq-any integer? (lq a 3.1 b 2.7)) => #f (lseq-any < (lq 3 1 4 1 5) (lq 2 7 1 8 2)) => #t
ievery
pred lseq1 lseq2 ... -> value
If there are n lseq arguments lseq1 ... lseqn, then pred must be a procedure taking n arguments and returning a boolean result.
lseq-every
applies pred to the first elements of the lseqi parameters.
If this application returns false, lseq-every
immediately returns false.
Otherwise, it iterates, applying pred to the second elements of the
lseqi parameters, then the third, and so forth. The iteration stops
when a false value is produced or one of the lseqs runs out of values.
In the latter case, lseq-every
returns
the true value produced by its final application of pred.
The application of pred to the last element of the lseqs
is a tail call.
If one of the lseqi has no elements, lseq-every
simply returns #t
.
Like lseq-any
, lseq-every
's name does not end with a question mark — this is to
indicate that it does not return a simple boolean (#t
or #f
), but a
general value.
lseq-index
pred lseq1 lseq2 ... -> integer or false
If there are n lseq arguments lseq1 ... lseqn, then pred must be a function taking n arguments and returning a boolean result.
lseq-index
applies pred to the first elements of the lseqi parameters.
If this application returns true, lseq-index
immediately returns zero.
Otherwise, it iterates, applying pred to the second elements of the
lseqi parameters, then the third, and so forth. When it finds a tuple of
lseq elements that cause pred to return true, it stops and returns the
zero-based index of that position in the lseqs.
The iteration stops when one of the lseqs runs out of values; in this
case, lseq-index
returns #f
.
(lseq-index even? (lq 3 1 4 1 5 9)) => 2 (lseq-index < (lq 3 1 4 1 5 9 2 5 6) (lq 2 7 1 8 2)) => 1 (lseq-index = (lq 3 1 4 1 5 9 2 5 6) (lq 2 7 1 8 2)) => #f
imember
x lseq [=] -> lseq
imemq
x lseq -> lseq
imemv
x lseq -> lseq
(lseq-drop lseq i)
for i less than the length of lseq.
If x does
not occur in lseq, then #f
is returned.
lseq-memq
uses eq?
to compare x
with the elements of lseq,
while lseq-memv
uses eqv?
, and
lseq-member
uses equal?
.
(lseq-memq 'a (lq a b c)) => (a b c) (lseq-memq 'b (lq a b c)) => (b c) (lseq-memq 'a (lq b c d)) => #f (lseq-memq (lseq 'a) (lq b (a) c)) => #f (lseq-member (lseq 'a) (lq b (a) c)) => ((a) c) (lseq-memq 101 (lq 100 101 102)) => *unspecified* (lseq-memv 101 (lq 100 101 102)) => (101 102)
The comparison procedure is used to compare the elements ei of lseq to the key x in this way:
(= x ei) ; lseq is (E1 ... En)
(lseq-member 5 lseq <)
Note that fully general lseq searching may be performed with
the lseq-find-tail
and lseq-find
procedures, e.g.
(lseq-find-tail even? lseq) ; Find the first elt with an even key.
idelete
x lseq [=] -> lseq
lseq-delete
uses the comparison procedure =, which defaults to equal?
, to find
all elements of lseq that are equal to x, and deletes them from lseq. The
dynamic order in which the various applications of = are made is not
specified.
The lseq is not disordered — elements that appear in the result lseq occur in the same order as they occur in the argument lseq. The result may share a common tail with the argument lseq.
Note that fully general element deletion can be performed with the lseq-remove
procedures, e.g.:
;; idelete all the even elements from LIS: (lseq-remove even? lis)The comparison procedure is used in this way:
(= x ei)
.
That is, x is always the first argument,
and an lseq element is always the
second argument. The comparison procedure will be used to compare each
element of lseq exactly once; the order in which it is applied to the
various ei is not specified. Thus, one can reliably remove all the
numbers greater than five from an lseq with
(lseq-delete 5 lseq <)
idelete-duplicates
lseq [=] -> lseq
lseq-delete-duplicates
removes duplicate elements from the
lseq argument.
If there are multiple equal elements in the argument lseq, the result lseq
only contains the first or leftmost of these elements in the result.
The order of these surviving elements is the same as in the original
lseq — lseq-delete-duplicates
does not disorder the lseq (hence it is useful
for "cleaning up" immutable association lists).
The = parameter is used to compare the elements of the lseq; it defaults
to equal?
. If x comes before y in lseq, then the comparison is performed
(= x y)
.
The comparison procedure will be used to compare each pair of elements in
lseq no more than once;
the order in which it is applied to the various pairs is not specified.
Implementations of lseq-delete-duplicates
are allowed to share common tails
between argument and result lseqs — for example, if the lseq argument
contains only unique elements, it may simply return exactly
this lseq.
Be aware that, in general, lseq-delete-duplicates
runs in time O(n2) for n-element lseqs.
Uniquifying long lseqs can be accomplished in O(n lg n) time by sorting
the lseq to bring equal elements together, then using a linear-time
algorithm to remove equal elements. Alternatively, one can use algorithms
based on element-marking, with linear-time results.
(lseq-delete-duplicates (lq a b a c a b c z)) => (a b c z) ;; Clean up an ialist: (lseq-delete-duplicates (lq (a . 3) (b . 7) (a . 9) (c . 1)) (lambda (x y) (eq? (lseq-first x) (lseq-first y)))) => ((a . 3) (b . 7) (c . 1))
An "immutable association list" (or "ialist") is an lseq of ipairs. The icar of each ipair contains a key value, and the icdr contains the associated data value. They can be used to construct simple look-up tables in Scheme. Note that ialists are probably inappropriate for performance-critical use on large data; in these cases, immutable maps or some other alternative should be employed.
iassoc
key ialist [=] -> ipair or #f
iassq
key ialist -> ipair or #f
iassv
key ialist -> ipair or #f
#f
is returned.
lseq-assq
uses eq?
to compare key
with the icar fields of the ipairs in ialist,
while lseq-assv
uses eqv?
and lseq-assoc
uses equal?
.
(define e (lq (a 1) (b 2) (c 3))) (lseq-assq 'a e) => (a 1) (lseq-assq 'b e) => (b 2) (lseq-assq 'd e) => #f (lseq-assq (lseq 'a) (lq ((a)) ((b)) ((c)))) => #f (lseq-assoc (lseq 'a) (lq ((a)) ((b)) ((c)))) => ((a)) (lseq-assq 5 (lq (2 3) (5 7) (11 13))) => *unspecified* (lseq-assv 5 (lq (2 3) (5 7) (11 13))) => (5 7)
The comparison procedure is used to compare the elements ei of lseq to the key parameter in this way:
(= key (lseq-first ei)) ; lseq is (E1 ... En)
(lseq-assoc 5 ialist <)
Note that fully general ialist searching may be performed with
the lseq-find-tail
and lseq-find
procedures, e.g.
;; Look up the first association in ialist with an even key: (lseq-find (lambda (a) (even? (lseq-first a))) ialist)
ialist-cons
key datum ialist -> ialist
(lambda (key datum ialist) (lseq-pair (lseq-pair key datum) ialist))Construct a new ialist entry mapping key -> datum onto ialist.
ialist-delete
key ialist [=] -> ialist
lseq-alist-delete
deletes all associations from ialist with the given key,
using key-comparison procedure =, which defaults to equal?
.
The dynamic order in which the various applications of = are made is not
specified.
Return values may share common tails with the ialist argument. The ialist is not disordered — elements that appear in the result ialist occur in the same order as they occur in the argument ialist.
The comparison procedure is used to compare the element keys ki of ialist's
entries to the key parameter in this way:
(= key ki)
.
Thus, one can reliably remove all entries of ialist whose key is greater
than five with
(lseq-alist-delete 5 ialist <)
These two procedures are analogues of the primitive
side-effect operations on pairs, set-car!
and set-cdr!
.
replace-icar
ipair object -> ipair
replace-icdr
ipair object -> ipair
These procedures convert between mutable and immutable pair structures.
pair->ipair
pair -> ipair
ipair->pair
ipair -> pair
list->lseq
flist -> lseq
lseq->list
lseq -> flist
These procedures return an lseq and a list respectively that have the same elements as the argument. The tails of dotted (lseq-)lists are preserved in the result, which makes the procedures not inverses when the tail of a dotted lseq is a list or vice versa. The empty list is converted to itself.
It is an error to apply list->lseq
to a circular list.
tree->itree
object -> object
itree->tree
object -> object
These procedures walk a tree of pairs or ipairs respectively and make a deep copy of it, returning an isomorphic tree containing ipairs or pairs respectively. The result may share structure with the argument. If the argument is not of the expected type, it is returned.
These procedures are not inverses in the general case. For example,
a pair of ipairs would be converted by tree->itree
to
an ipair of ipairs, which if converted by lseq-tree->tree
would produce a pair of pairs.
gtree->itree
object -> object
gtree->tree
object -> object
This procedure allows a procedure to be applied to an lseq.
iapply
procedure object ... lseq -> object
lseq-apply
procedure is an analogue of apply
whose last
argument is an lseq rather than a list. It is equivalent to
(apply
procedure object ... (lseq->list
lseq))
,
but may be implemented more efficiently.
ipair-comparator
lseq-comparator
object is a SRFI-114 comparator suitable for comparing lseqs.
Note that it is not a procedure.
It compares pairs using default-comparator
on their first elements. If they are not equal, that value is returned. If they are equal, default-comparator
is used on the rest of the lseqs and that value is returned.
make-lseq-comparator
comparator -> comparator
make-lseq-comparator
procedure returns a comparator suitable for comparing lseqs
using element-comparator to compare the elements.
An lseq is a SRFI 117 queue plus a generator. Queues can be shared between lseqs, which means that you are not allowed to remove anything from them, and the only addition operation is lseq-realize-once!
, which realizes one value and adds it to the back of the queue.
The sample implementation of this SRFI depends on SRFI 9 (or R7RS) records. The files in the implementation are as follows:
FIXME
Without the work of Olin Shivers on SRFI 1, this SRFI would not exist. Everyone acknowledged there is transitively acknowledged here. This is not to imply that either Olin or anyone else necessarily endorses the final results, of course.